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Review for Sections 2.1 and 2.2
https://www.youtube.com/watch?v=Lalm4fubOOI
What happens if you drop a watermelon off a 100 foot building???
Well we know that the position can be found by s(t )  16t 2  100 .
Let’s approximate the instantaneous velocity of the watermelon at time t = 1.
What is the average velocity (average r.o.c.) from 1 second to 2 seconds?
s (2)  s (1)

2 1
What is that average velocity over the interval t = 1 to t = 1.1?
s (1.1)  s (1)

1.1  1
Now let’s use the definition of the derivative to see how fast the watermelon was falling to the
ground after 1 second.
lim
h 0
f (1  h)  f (1)

1 h 1
Let’s use the power rule to find the velocity (derivative) at 1 second.
Fly UP